SERIES CIRCUITS
When
all the parts of a circuit are electrically connected
end to end, they are said to be in series.The current flows from the battery E through the resistor R1, then through the resistor R2, and returns to the battery E.
The
total resistance of a series circuit is equal to the sum of the individual resistances. If R1 and
R2 are the series resistors, then their total
resistance is: R= R1 + R2.
Thus, if R1 is 5 ohms and R2 is 10 ohms then:R = 10 + 5 = 15 ohms
There are three
fundamental laws that apply to any series
circuit. These laws are:
- In a series circuit, the same current flows through each component in the circuit.
- In a series circuit, the total resistance is the sum of the individual resistance's making up the circuit.
- In a series circuit, the applied voltage is equal to the sum of the individual voltage drops.
PARALLEL CIRCUITS
When two or more electrical devices are connected so that each one offers a separate path for the flow of the current between two points, the devices are said to be in parallel. In the figure below, the two resistors R, and R2 are shown connected in parallel.
The
total current set up by the battery divides at point A, a part going through the resistor R1
while the
other part flows through the resistor R2. At the junction point of B, the two currents unite and return to the battery. The resistor R2 is in
parallel with resistor R1. Similarly, the resistor R1 is in parallel with resistor R2.
The
two branch circuits consisting of the resistors R1 and R2 form two
separate paths in parallel. An open circuit in either branch will not stop the
flow of current through the other branch, because
each branch
forms a separate and complete path from point
A to point B. An open circuit in the main conductors,
between point A or B and the battery, would interrupt the current in the entire circuit.
The
total current in a parallel circuit is the sum of the currents in each branch. Since each branch is connected
directly to the battery, the current in it is calculated
according to Ohms Law. If the battery voltage
E is 30 V and R1 is 5 ohms, then the current in R1
is E / R1 or 30 / 5 = 6 amps. If R2 is 10 ohms, the current in it is 30 / 10 = 3 amps. The total current
is the summation of the branch currents, or I1 + 12 = IT . Thus 6 + 3 = 9.
Since
the combined current in the two parallel resistors is 9 amps and the
voltage is 30, according to Ohms Law the two
resistors in parallel must have a
resistance RT = E / I = 30 / 9 = 3 1/3 ohms, which is less than the resistance of either resistor.
Laws for Parallel
Circuits
The
facts pointed out concerning parallel circuits may be
summarized in the
form of three fundamental
laws which will apply to any parallel circuit.
These laws are:
- In a parallel circuit, the same voltage is applied to each individual branch.
- In a parallel circuit, the total current is equal to the sum of the currents in the individual branches.
- In a parallel circuit, the effective resistance is equal to the applied voltage divided by the total current, and this value is always less than the smallest resistance contained in the circuit.
Unit of Resistivity
From
what has been discussed regarding series circuits, it would be a reasonable conclusion to say that the resistance of a conductor increases
as its length increases. By the same token,
from what has been said regarding parallel circuits,
the resistance of a conductor must decrease as its cross-sectional area increases.
Experiments
have proven this true, and it is found that the resistance is proportional to the
length and that the resistance is inversely proportional
to the cross-sectional area.
To
mathematically relate these for any conductor, we must introduce proportionality constant,
called Resistivity whose symbol is the Greek letter ρ
(rho). Combining all of these factors, we can express
the resistance of any conductor by, R=ρL/A or ρ=RA/L
Since
R is in ohms, and if A is in square centimeters (cm^2), and L is in centimeters
(cm), then:
ρ=ohms x cm^2/cm=ohm-cm
Thus ρ,
that is, Resistivity
has the dimension ohm-centimeter. Resistivity then is equal to the resistance of a conductor which is 1
centimeter long with a constant cross-sectional area of 1 square centimeter.
ELECTRICAL
INSTRUMENTS
Meter Movement Sensitivity and Accuracy
The sensitivity of a
meter movement depends upon the amount of current necessary to operate
the moving element of the meter. The
meter movement requiring the least amount of current
for full scale deflection is considered to be the
most sensitive.
The amount of current necessary for
full scale deflection depends upon the number
of turns of wire on
the moving coil. When more turns are added, a stronger magnetic field is created; thus, less current is necessary for full scale deflection.
Ammeters
The
ammeter is the instrument used to indicate the quantity
of current in an electrical circuit. In order to
measure the amount of current in a circuit, the ammeter
must be placed in series with the circuit. The
figure below shows a DC ammeter connected into
an electrical circuit.
The two
resistors, R and
RV, represent the resistance of the ammeter and the over-all
circuit, respectively. When the ammeter is manufactured, the resistance RA is kept as small as
possible so that the value current indicated by the movement
will be close to the actual circuit current when the ammeter is removed. Note that the ammeter has
polarized terminals to indicate proper circuit
connection of the ammeter.
The
ammeter shown in the figure above has the disadvantage of being able to indicate only one range of current. To measure higher values of
direct current,
the meter may
incorporate a suitable resistor called a meter shunt connected in
parallel with the meter movement as shown in the below figure.
For
full scale deflection of the meter pointer, the meter shunt provides a path for the portion of
the current in excess of that required by the
sensitivity of the meter movement. Assume that the
movement sensitivity of the meter in the above figure
is one ampere. With the addition of the proper shunt resistance, the ammeter circuit allows a total
of 5 amperes to pass before the pointer indicates
full-scale deflection -- 4 amperes through the shunt and 1
ampere through the movement; therefore, the maximum current reading ability of the ammeter has been increased by the addition of the
shunt resistor.
Determination of
the correct value
of shunt resistances
for different meter
movements and current ranges can be accomplished by using
Ohms Law as applied to parallel circuits. The
following illustrates a typical problem in the
calculation of a meter shunt. The meter movement shown below
has a
full-scale deflection sensitivity
of one milliampere.
It is desired to connect a shunt resistor to increase the current indicating capability
of the movement to ten milliamperes. Since the
movement can
safely handle only
one milliampere, nine milliamperes must flow through the shunt.
Expressing the
current through the shunt resistance in terms
of commonly used symbols provides the following
relationship:
Is = It - Im
where:
Is
= current through the shunt
It = total current to be measured
It = total current to be measured
Im = current through the meter
Since
the internal resistance of the meter is shown to
be 45 ohms, the shunt must have one-ninth of this resistance or a resistance of 5 ohms to carry the required current.
To
prove the above statement, the following should be
considered. Knowing that the current through the meter
movement is one milli-ampere (Im) and its resistance
is 45 ohms (Rm), the voltage drop across the meter can be calculated by Ohms Law.
Em = Im x Rm
Em = 0.001 x 45
Em = 0.045 volt
Em = 0.001 x 45
Em = 0.045 volt
Since the
voltage across the
network (meter movement and shunt) is known, further
application of Ohms
Law will provide
the resistance requirement of the shunt.
RS = ES/IS
RS = 0.045/0.009
RS = 5 ohms
Through mathematical
substitution, a standard formula
can be established for determining the required
resistance of any meter shunt, providing the current
through the shunt
is known. The standard
formula is:
R = (Im x Rm)/Is
Effect of Ammeter Resistance on Circuit Resistance
When
an ammeter is inserted in an electrical circuit, it increases the effective
circuit resistance. This will reduce the current flow in the circuit
in accordance with Ohm's Law.
The practical
effect may or may not
be a consideration depending upon the relative
values of the
original circuit resistance
and the inserted ammeter
resistance. The ammeter
should, in general, ever have a resistance that is greater that 1% of the circuit resistance into which it is
being inserted.
Voltmeters
The
voltmeter is the instrument used to indicate the quantity of voltage present in an electrical
circuit. In order to correctly measure the voltage of a
circuit or circuit component, the voltmeter must be placed in parallel with the circuit. A DC voltmeter is capable of measuring only DC voltages, since the
current must
pass through the
meter movement in a specified direction.
The
following figure shows the internal components of a voltmeter (enclosed in dotted lines),
which is connected as a unit to a circuit for the
measurement of
voltage. Note that
the voltmeter circuit
is composed of an ammeter in series with a
resistor (Rm). The resistance, Rm, is a high-value
resistance placed in series with the meter movement resistance to reduce the amount of current flowing through the movement.
As
illustrated, when the voltmeter is placed across the circuit component, R1, the current flowing through the voltmeter causes a deflection of
the meter needle. The resistance, Rm, is called
the multiplier resistance because, if its ohmic
value is increased,
the same current would still be required to cause
full-scale deflection of
the meter movement, but more voltage would be required to cause this current to flow.
If
we experimentally set up the circuit as shown in the
figure below we can determine the resistance of the
coil assuming that the required current is 1
milli-ampere for full scale deflection.
By
adjusting the variable resistor until the meter reads full scale (.001 ampere), we know that the total circuit resistance (meter plus resistor value) must be 1000 ohms. Assume that the variable resistor was measured and found to be 950
ohms, then the meter coil itself must be only 50
ohms. Thus, the basic instrument has a 50 milli-volt
drop movement.
E = IR = 0.001*50 = .050volts
From this we have seen that in order to use this basic instrument as a voltmeter, we had to add series resistance. In this case the total circuit resistance is 1000 ohms. Thus, by definition, this instrument, when used as a voltmeter, would have a sensitivity of 1000 ohms per volt.
R = E/I = 1/0.001 = 1000 ohms
Normally, sensitivity is expressed in the fashion --ohms per volt. Thus, when you read on the face of a meter its sensitivity, you can, of course, determine the current required for full scale deflection, but you do not know the basic movement resistance.
From the case illustrated, it is obvious that in order to use any meter as a voltmeter, it is necessary that the internal resistance be known. We can then produce a voltmeter to read any voltage utilizing a basic formula.
E = Im x Rm + Im x Rs
where:
Im = meter current
Rm = meter resistance
Rs = series resistance
E = desired voltage range:
Rs = Em/Im - Rm
Then to produce a 100 volt full range instrument with the basic movement that has 50 ohms resistance and 0.001 ampere sensitivity, the necessary series resistor is:Rs = 100/0.001 - 50 = 99,950 ohms The series resistors required for the voltmeter ranges are known as multiplier resistors.Suppose that it is desired to know the voltage appearing across the load in the figure below.
Now
we know from the circuit values given that a current of .001 ampere must be flowing in the circuit. The voltage drop appearing across the
10 K ohm load resistor must be 10 volts. Now, if a 1000 ohm per volt meter with a full scale of 10
volts (that is a total resistance of 10 K) were placed in parallel with load, parallel resistance of the load
and meter must be 5 K.
The
circuit resistance then is 95 K, and the total current
per Ohms Law (100 volts / 95,000 ohms) must be
.001053 ampere. The voltage as read by the meter
then must be:
E = .001053 x 5000 = 5.263 volts
From
the circuit conditions set up, we know it should have read 10 volts.
Therefore, the voltmeter itself has
introduced a large magnitude of error, and in terms of percent this is:
%
error = [1 - (observed voltage/true voltage)] x 100% % error = [(1 - (5.26/10)]
x 100% = 47.4%
We
can draw two conclusions from the explanation above.
- Any voltmeter, since it is a current-operated device, will introduce an error.
- To minimize error, the sensitivity of the meter must be high. That is, the smaller the current, the more accurate the reading will be.
THE DIGITAL DIRECT CURRENT INSTRUMENT
Digital
instruments are a
relatively recent innovation
as compared to
the moving needle analog
instruments. They have many advantages making them particularly useful to the
corrosion control worker on underground structures.
There are also some disadvantages. The development and improvement of such instruments is a
continuing thing with new advances in electronic
technology. The corrosion worker will do well to keep abreast of such developments to assure himself that he
is equipped with the best available equipment for
his purposes.
Operating Principles
The
figure below is a representation of a digital instrument for the purpose of illustrating
some of the pertinent points concerning such devices.
No attempt is made to diagram the electronic
circuitry the details of which can be quite complex and which can vary with the instrument
manufacturer.
Whereas the analog instruments described earlier have mechanically moving parts, a digital readout instrument is entirely electronic with no moving parts. Although the figures in the digital readout module may appear to move as the indicated reading changes, this is simply the changing formation of the digital characters as the applied electrical signal changes. There is no actual physical movement.
There
are two types of digital readout modules. One of
these utilizes LED (light emitting
diode) elements to form the characters in the
readout. As the name implies, when such a diode is
energized by an electrical signal, it shows up
as bars of light.
The
other type of readout utilizes LCD (liquid crystal diode) elements. Such a diode is normally a neutral light color because it reflects
light, but when energized by an electrical signal, it
appears as a dark bar (absorbs light) which
contrasts with the light
background color. Of
the two types,
the liquefied crystal readouts
are normally used in corrosion test instruments for field use since they take less energy from the instrument
batteries and can be easily read in bright
sunlight. The discussion herein
assumes that liquefied
crystal readout displays will be used.
One of the more
important differences between the analog instruments
described earlier and a digital instrument
is the fact that all the energy needed to operate a moving coil analog instrument has to come from
the external circuit
in which measurements
are being made.
The digital instrument, on the other hand, takes very little energy from the external circuit. The energy
needed to operate its circuitry comes from internal long-life batteries in these electronic instruments.
When the digital
instrument is used as a voltmeter, the
unknown input voltage
at the instrument terminals bypasses the ammeter shunt
module and is applied to the DC amplifier module.
Here the applied voltage encounters a high
input resistance --typically ten million ohms or higher. This will be a fixed value which will be the same
regardless of the voltage readout range selected. This very high input
resistance means that the current taken from the external circuit will be very small and thus the reading will be more accurate. Although, as indicated, the input resistance normally remains constant for all voltage ranges, there are some digital instruments for corrosion work which have a provision
for changing the input resistance (by pressing a button or
rotating a selector switch) in order to see if the reading remains essentially
the same with both values of input resistance. If they are the same, this indicates that external circuit resistance is not a problem. If there is a difference between the two readings, interpretive techniques may be used to arrive at the true potential.
resistance means that the current taken from the external circuit will be very small and thus the reading will be more accurate. Although, as indicated, the input resistance normally remains constant for all voltage ranges, there are some digital instruments for corrosion work which have a
The
direct current amplifier, as its name implies, amplifies
the input signal to a value that will actuate the
readout module after adjustment using the range selector
module.
In
addition to the numerical figures (or digits) in the readout module, the decimal point will
appear in its correct location for the range that has been
selected.
If the voltage being measured has been
incorrectly connected to the instrument (+) to (-) and (-) to (+) instead of (+) to (+) and (-) to (-) as it should be, or if the polarity of the input voltage changes,
a (-) sign will normally appear on the
readout panel. Depending on the manufacturer, other
information may appear as well, such as a low battery indicator when instrument batteries need replacement. There may also be an indication to show if an
applied voltage or current is beyond the
range selected.
When the instrument
is used in the ammeter mode, shunt resistors are used for various
current ranges as has been described earlier for analog
instruments. The voltage drop across the shunts
is then applied to the
electronic circuitry as
described for the voltmeter mode with the measured value appearing on the readout module. An important difference from the analog ammeter described
earlier is that less energy is taken from the external
circuit since most of the instrument operating
energy comes from its internal batteries. Since
shunts are used for the ammeter mode, the discussion
relating to the effect of the shunt resistances on
the external circuit is generally similar to that discussed
under analog instruments.
Accuracy
Digital instruments, being non-mechanical, can be made with greater accuracy than analog instruments in the same price bracket. Normally, the accuracy of a digital instrument is expressed differently from that of an analog instrument as discussed earlier. This may be expressed, for example, as ± (plus or minus) a percentage of the actual reading, ± a percentage of the full scale reading, ± one digit in the last place (right hand figure) of the indicated readout. The net percentage accuracy figures can be quite high (depending on manufacturer and quality) as compared with analog instruments.
Advantages
Some of the advantages of digital instruments compared with analog instruments are as follows.
- High input resistance to electronic circuit with very little energy taken from the external circuit in which measurements are being taken.
- High accuracy.
- Decimal point shown in correct location, thus reducing possibility of human error.
- No interpretation of needle position necessary between divisions (as often required with analog instruments) thus further reducing the possibility of human error.
- No polarity problem -- instrument reads correctly regardless of polarity as long as the reversed polarity indicator (negative sign) is observed.
- Relatively rugged for field use.
Disadvantages
Nothing is perfect. There are some disadvantages with respect to digital instruments although certain of these are subject to improvement. Typical disadvantages are as follows:
- Taking readings under dim light conditions where liquid crystal readouts may be relatively difficult to see.
- Certain components of the electronic circuitry may have a narrower operable temperature range than analog instruments.
- Liquid crystal read-out panels tend to be sluggish at low temperatures and tend to blank out if the temperature is too high. In extreme cases, the readout panel can be permanently damaged by excessive temperature.
- Reading continuously varying values. In some types of corrosion control work, voltages and currents being measured may be subject to continuous variation rather than being a steady value. Stray current situations are an example. In such situations, the digital readout panel can be a confusing display of continuously changing digits making it difficult to determine or estimate, maximum, minimum and average figures. Although still difficult, this can be more readily done with an analog instrument.
- In order to get the advantages of electronic circuitry and still permit an analog readout, hybrid instruments are available which use the electronic circuitry to operate an analog readout. Such instruments retain the advantage of minimal operating energy taken from the external circuit since the energy needed to operate the analog readout is provided by the instrument internal batteries.
COMBINATION
INSTRUMENTS
For use in corrosion control work, combination instruments have been developed which,
typically, have two indicating instruments with interconnecting circuitry
and selector switches. These
are so arranged that various testing requirements may be
set up by
proper switch settings. This reduces the wiring as compared
to that needed for separate instruments. Time
needed to
set up for
a particular test
is reduced and possibilities of wiring errors are reduced. Additionally, single-instrument multi-testers
are available (both analog and digital) which measure both DC voltage and current as has been
discussed. but in addition can measure AC voltage and (in some
instances) AC current
and can measure resistance. Such instruments are a great convenience
to the underground corrosion control worker.
CLAMP-ON INSTRUMENTS
A specialized type of
instrument is available which is
useful for measuring
currents in conductors where it is desired to do so without interrupting the circuit.
These are called
clamp-on instruments. These typically incorporate a split
or hinged ring of magnetic core material which is
clamped around the conductor in which current is to be measured.
Clamp-on
instruments are available to measure both AC current and DC current. The sensing device may differ between the two types. Instruments designed for AC current measurement can
measure an induced voltage in a coil surrounding the ring at one
point with the
induced voltage being proportional to the amount of current flow through the conductor. The instrument designed for DC current measurement electronically senses
the distortion in the magnetic field in the
clamp-on ring caused by the continuous mono-directional current flow.
Both
types of instruments are available to cover a wide
range of full scale current.At
least one maker of DC clamp-on instruments can supply
clamp-on rings in various diameters from smaller
sizes for wires or cables to large rings that can
surround pipes.
COMPUTER-COMPATIBLE
INSTRUMENTS
With the
continuing development of
computer usage,
the appearance of
computer-compatible field-testing instruments was
inevitable. Typically, this is an adjunct to electronic testing
instruments that permits the corrosion worker to store recorded data on command in some form of internal
storage device (RAM, ROM, tape, disc, etc.)
incorporated in the instrument. Numerical measurements can be supplemented with coded information as to
location and type of test plus supplementary
information appropriate to the test being
made. This data can also normally be recorded and then
downloaded into a PC computer for more detailed
analysis while in the field Storing
information in the above fashion reduces field time in data taking. The stored information
can also
be later transferred to a desktop computer that can
be used to record, analyze and process the data in accord with record keeping programs that have been
developed for the
operating company's purpose.
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